18/06/16 01:07:31.76 Sq4cRvDq.net
>>137
log[2](6) = ln(6)/ln(2) = 1 + ln(3)/ln(2)
2^3 = 8 < 9 = 3^2 より ln(3)/ln(2) > 3/2 = 1.5
3^5 = 243 < 256 = 2^8 より ln(3)/ln(2) < 8/5 = 1.6
∴ 2.5 < log[2](6) < 2.6
また 2.6 - 2.5 = 0.1 < 1/9,
(p，q) = (2，5) (5，13)
18/06/16 01:07:31.76 Sq4cRvDq.net
>>137
log[2](6) = ln(6)/ln(2) = 1 + ln(3)/ln(2)
2^3 = 8 < 9 = 3^2 より ln(3)/ln(2) > 3/2 = 1.5
3^5 = 243 < 256 = 2^8 より ln(3)/ln(2) < 8/5 = 1.6
∴ 2.5 < log[2](6) < 2.6
また 2.6 - 2.5 = 0.1 < 1/9,
(p，q) = (2，5) (5，13)