13/04/20 23:23:49.36
>>85
original series
Γ(a) = Σ[k=0,∞) (1/2π)^{k(k-1)/2} a^k
= 1 + a + aa/2π + (a/2π)^3 + ･････
13/04/20 23:23:49.36
>>85
original series
Γ(a) = Σ[k=0,∞) (1/2π)^{k(k-1)/2} a^k
= 1 + a + aa/2π + (a/2π)^3 + ･････
13/04/20 23:23:49.36
>>85
original series
Γ(a) = Σ[k=0,∞) (1/2π)^{k(k-1)/2} a^k
= 1 + a + aa/2π + (a/2π)^3 + ･････