20/08/09 23:21:31.30 dFp53gtH.net
>>226 Python3
s = "D a B c d c C A E c e B b".split();
d = {}
for c in s:
u = c.upper()
if u in d: d[u] += ' ' + c
else: d[u] = c
ks = sorted(d.keys())
print(' '.join(map(lambda x: '(%s)' % d[x], ks)))
実行結果
~ $ py 18_221_NCS_sort_grp.py
(a A) (B B b) (c c C c) (D d) (E e)