19/03/10 13:31:21.17 vqbsu7fW.net
>>571
Haskell
main = do
putStrLn $ seclet "abc" (==) 2
putStrLn $ seclet "abc" (/=) 2
seclet lst func num = seclet' lst func 1 num
where
seclet' [] _ _ _ = []
seclet' (x:xs) f n a | f n a = x: seclet' xs f (n + 1) a
seclet' (_:xs) f n a = '*': seclet' xs f (n + 1) a