10/05/20 16:50:10
>>152
与式 ⇔ (x-y)(x^2-xy-y^2)=1
(x-y, x^2-xy-y^2)=(1,1), (-1,-1)
∴ (x, y) = (1,0) , (2,1) , (0,1) , (-3,-2)
10/05/20 16:50:10
>>152
与式 ⇔ (x-y)(x^2-xy-y^2)=1
(x-y, x^2-xy-y^2)=(1,1), (-1,-1)
∴ (x, y) = (1,0) , (2,1) , (0,1) , (-3,-2)
10/05/20 16:50:10
>>152
与式 ⇔ (x-y)(x^2-xy-y^2)=1
(x-y, x^2-xy-y^2)=(1,1), (-1,-1)
∴ (x, y) = (1,0) , (2,1) , (0,1) , (-3,-2)