10/01/05 17:18:38
>>71
(1/x) + (1/y) = 3 のとき x+y - 3xy = 0
(2x-3xy+2y)/(x+y) = (x+y +(x+y-3xy))/(x+y) = (x+y)/(x+y) = 1
10/01/05 17:18:38
>>71
(1/x) + (1/y) = 3 のとき x+y - 3xy = 0
(2x-3xy+2y)/(x+y) = (x+y +(x+y-3xy))/(x+y) = (x+y)/(x+y) = 1
10/01/05 17:18:38
>>71
(1/x) + (1/y) = 3 のとき x+y - 3xy = 0
(2x-3xy+2y)/(x+y) = (x+y +(x+y-3xy))/(x+y) = (x+y)/(x+y) = 1