09/06/21 12:18:31
>>371
a(n+1)
=∫[x=n,n+1] (e^(-kx) *f(x))dx
=∫[t=n-1,n] (e^(-k(t+1)) *f(t+1))dt
=∫[t=n-1,n] (e^(-kt)*e^(-k) *f(t+1))dt
=e^(-k)∫[t=n-1,n] (e^(-kt)*f(t+1))dt
=e^(-k)∫[t=n-1,n] (e^(-kt)*f(t))dt
=e^(-k)*a(n)
09/06/21 12:18:31
>>371
a(n+1)
=∫[x=n,n+1] (e^(-kx) *f(x))dx
=∫[t=n-1,n] (e^(-k(t+1)) *f(t+1))dt
=∫[t=n-1,n] (e^(-kt)*e^(-k) *f(t+1))dt
=e^(-k)∫[t=n-1,n] (e^(-kt)*f(t+1))dt
=e^(-k)∫[t=n-1,n] (e^(-kt)*f(t))dt
=e^(-k)*a(n)