08/11/29 00:32:53
>>602
∫[0,2π]cost/(1+(sint)^2)dt
= ∫[0,π/2]cost/(1+(sint)^2)dt
+ ∫[π/2,π]cost/(1+(sint)^2)dt
+ ∫[π,3π/2]cost/(1+(sint)^2)dt
+ ∫[3π/2,2π]cost/(1+(sint)^2)dt
= ∫[0,1]1/(1+x^2)dx
+ ∫[1,0]1/(1+x^2)dx
+ ∫[0,-1]1/(1+x^2)dx
+ ∫[-1,0]1/(1+x^2)dx
= ∫[0,0]1/(1+x^2)dx
= 0
？？？？