08/02/29 03:51:19
>654
[3問目]
2^(3m) + 2 = 4n + 2,
2^(4n+2) = 4^(2n+1) ≡ (-1)^(2n+1) = -1 (mod 5)
∴ 5 の倍数…
08/02/29 03:51:19
>654
[3問目]
2^(3m) + 2 = 4n + 2,
2^(4n+2) = 4^(2n+1) ≡ (-1)^(2n+1) = -1 (mod 5)
∴ 5 の倍数…
08/02/29 03:51:19
>654
[3問目]
2^(3m) + 2 = 4n + 2,
2^(4n+2) = 4^(2n+1) ≡ (-1)^(2n+1) = -1 (mod 5)
∴ 5 の倍数…