04/11/30 22:52:14
>>708
> 左辺 = x/(y+1) +y/(z+1) +z/(x+1) = [3u +(s^2 -2t) +t +s]/[(x+1)(y+1)(z+1)].
2番目の等号は≧の間違えでしょ。
04/11/30 22:52:14
>>708
> 左辺 = x/(y+1) +y/(z+1) +z/(x+1) = [3u +(s^2 -2t) +t +s]/[(x+1)(y+1)(z+1)].
2番目の等号は≧の間違えでしょ。
04/11/30 22:52:14
>>708
> 左辺 = x/(y+1) +y/(z+1) +z/(x+1) = [3u +(s^2 -2t) +t +s]/[(x+1)(y+1)(z+1)].
2番目の等号は≧の間違えでしょ。