22/12/09 21:09:01.73 T+YnZBA1.net
w^3+x^3+y^3=z^3
Use ζ(2) to check whether the formula w^3+x^3+y^3=z^3 holds for all integers.
It becomes 2×3ζ(3) with ± from the integer.
6×ζ(3)⇔ζ(2)=π^2/6⇔ζ(3)⇔π^2
Therefore, since it converges, an integer is spewed out from the divergence of ζ(3)!
So integers exist.
So we found 42 with computer power!