05/07/05 17:24:47
>>514の続き
[出力結果]----------------------------------------------------------------
.1> false-clause
.2> n=(a)
.3> k=#<closure (x) x>
..>
.4> true-clause
.5> n=()
.6> k=#<closure (u)
..> (write (quote sub-clause)) (newline) \
..> (write (quote k=)) (write k) (newline) \
..> (write (quote n=)) (write n) (newline) \
..> (write (quote u=)) (write u) (newline) \
..> (k (append n u))>
..>
.7> n=(a)
.8> k=#<closure (x) x>
.9> u=()
10> (a)
のような結果が得られます。