07/11/13 21:35:40
>>428
if(a==0) {
if(b==0) {
if(c==0) printf("It is trivial!\n");
else printf("Boo-boo!\n");
}
else {
x1 = -c / b;
printf("x=%.2f\n", x1);
}
}
else {
D = b * b - 4 * a * c;
if(D >0) {
x1 = (-b+sqrt(D)) / (2 * a);
x2 = (-b-sqrt(D)) / (2 * a);
printf("x=%.2f,%.2f\n", x1, x2);
}
else if(D==0) {
x1 = -b / (2 * a);
printf("x=%.2f\n", x1);
}
else printf("There exist no real-valued solutions.\n");
}
return 0;
}