07/07/16 21:34:45
>>102
#include <stdio.h>
double f(double x){
return 1.0/(1.0+x*x);
}
int main(void){
double a=0.0, b=10.0, h, sum;
long n=10000000, i;
h=(b-a)/n;
sum=f(a)+f(b);
for(i=1;i<n;i+=2) sum+=2*f(a+h*i);
for(i=2;i<n;i+=2) sum+=4*f(a+h*i);
sum*=h/3;
printf("Answer: %f\n", sum);
return 0;
}