15/11/25 22:06:58.44
d=1の時
α=(2α+1)(β-γ)
α=(2α+1)(2β+α)
β=(α^2)/(2α+1)
=(α^2)p(α)
=6α^3-3α^2-4α
=2(3α+1)-3α^2-4α
=-3α^2+2α+2
α=-(2α+1)(α+2γ)
γ=-α(α+1)/(2α+1)
=-(α+1)αp(α)
=-(α+1)(6α^2-3α-4)
=-6α^3-3α^2+7α+4
=-2(3α+1)-3α^2+7α+4
=-3α^2+α+2
f(x)=-3x^3+2x+2
g(x)=-3x^2+x+2