17/08/21 01:10:43.27 0.net
n=6: χ=11+...
n=5: χ≒9+25/11
n=4: χ≒7+16/(9+25/11)
n=3: χ≒5+9/(7+16/(9+25/11))
n=2: χ≒3+4/(5+9/(7+16/(9+25/11)))
n=1: χ≒1+1/(3+4/(5+9/(7+16/(9+25/11))))
π≒(2^2)/(1+1/(3+4/(5+9/(7+16/(9+25/11)))))
Google先生の回答(「すべてのキーワードを含む」に「π≒」以下をコピペして検索):
3.14146341463