18/06/29 21:30:16.76 zpGshx3p.net
>>312
shoot C:
0.7*(0.5*0.3+0.5*(0.3+0.7*0.5*0.3+(0.7*0.5*0.3)^2+...)
=0.7*(0.5*0.3+0.5*(0.3+0.105/(1-0.105)))
=0.251061452514
shoot B:
0.3*0.5*((0.7*0.5*0.3)+(0.7*0.5*0.3)^2+...)+0.7*0.3
=0.3*0.5*0.105/(1-0.105)+0.7*0.3
=0.227597765363
と思いきや
Thus hitting B and finishing off with C has less probability of winning for A than just missing the first shot.
So A fires his first shot into the ground and then tries to hit B with his next shot. C is out of luck.
というオチであった。
選択肢にない狡い答の気がするんだが。