18/08/31 12:51:45.85 F0nmV/5C.net
draft
√(1+x) = a + bx + cx2 + dx3 + ....
x = 0 , a=1
√(1+x) = (1 + bx + cx2 + dx3 + ....)(1 + bx + cx2 + dx3 + ....)
1 + x = 1 + 2bx + (b2+2c)x2 + (2d+2bc)x3 + ...
b=1/2
b2+2c=0, c=-1/8
2d+2bc=0,d=1/16
√(1+x) = 1+ x/2 -x2/8+ x3/16 + ....