24/04/21 23:52:54.00 85p+UetF.net
>>398
与式 = ∫[0,1] x' log(x^2+1) dx
= log(2) - ∫[0,1] 2x^2/(x^2+1) dx
= log(2) - ∫[0,1]{2-2/(x^2+1)}dx
= log(2) - 2 + π/2
24/04/21 23:52:54.00 85p+UetF.net
>>398
与式 = ∫[0,1] x' log(x^2+1) dx
= log(2) - ∫[0,1] 2x^2/(x^2+1) dx
= log(2) - ∫[0,1]{2-2/(x^2+1)}dx
= log(2) - 2 + π/2