23/01/22 03:37:46.01 wH4BXIfK.net
>>72
Wolfram先生によると実数解は
x = 1/(2 sqrt(3/(2 + (89 - 6 sqrt(159))^(1/3) + (89 + 6 sqrt(159))^(1/3)))) - 1/2 sqrt(4/3 - 1/3 (89 - 6 sqrt(159))^(1/3) - 1/3 (89 + 6 sqrt(159))^(1/3) + 4 sqrt(3/(2 + (89 - 6 sqrt(159))^(1/3) + (89 + 6 sqrt(159))^(1/3))))
x = 1/(2 sqrt(3/(2 + (89 - 6 sqrt(159))^(1/3) + (89 + 6 sqrt(159))^(1/3)))) + 1/2 sqrt(4/3 - 1/3 (89 - 6 sqrt(159))^(1/3) - 1/3 (89 + 6 sqrt(159))^(1/3) + 4 sqrt(3/(2 + (89 - 6 sqrt(159))^(1/3) + (89 + 6 sqrt(159))^(1/3))))