23/01/04 08:52:31.63 46MYnRh2.net
>>356
lim[n->∞] ∫[0,π/2] {sin(x)}^(1/n) dx = π/2
なぜならば、0<2x/π<sin(x)<1 [0<x<π/2]
23/01/04 08:52:31.63 46MYnRh2.net
>>356
lim[n->∞] ∫[0,π/2] {sin(x)}^(1/n) dx = π/2
なぜならば、0<2x/π<sin(x)<1 [0<x<π/2]
23/01/04 08:52:31.63 46MYnRh2.net
>>356
lim[n->∞] ∫[0,π/2] {sin(x)}^(1/n) dx = π/2
なぜならば、0<2x/π<sin(x)<1 [0<x<π/2]