22/12/05 20:39:13.00 axgXsy8Y.net
ζ(2) is 6-dimensional
ζ(3) is x^3+y^3+z^3=42
therefore
3↑ζ(3)=42
Than
↑ζ(3)≒3.5 dimensions
ζ(4) has 9↑10 dimensions
What is ζ(5)?
☆945=3^3×5×7
ζ(6) is
945=900+45=
9(100+9↑5)=9(10^2+9↑5)=
9(2^2↑5^2+9↑5)=
9(2^2↑5+9)↑5=
9↑(2^2+1)↑5^2=
9↑5^3 dimensions
What is ζ(7)?
9450= 2×3^3×5^2×7
9450≒945↑10=
9↑5^3↑10
ζ(8) has 9↑5^3↑10 dimensions
ζ(5)≒945↑10 dimensions
ζ(7)≒945↑10 dimensions