21/02/04 02:54:44.46 KkALMUyo.net
>>781
1 + x < e^x (x≠0)
より
1 - 1/n < e^{-1/n},
(1 + 1/(n-1))^n = (n/(n-1))^n = ((n-1)/n)^{-n} = (1 - 1/n)^{-n} > e,
n → n+1
(1 + 1/n)^{n+1} > e,
21/02/04 02:54:44.46 KkALMUyo.net
>>781
1 + x < e^x (x≠0)
より
1 - 1/n < e^{-1/n},
(1 + 1/(n-1))^n = (n/(n-1))^n = ((n-1)/n)^{-n} = (1 - 1/n)^{-n} > e,
n → n+1
(1 + 1/n)^{n+1} > e,