20/12/03 03:22:07.65 EylvoCB2.net
>>841
x = -3/(5+4sinθ),
y = 4(cosθ)/(5+4sinθ),
ところで
(4+5sinθ)^2 + (3cosθ)^2 = (5+4sinθ)^2,
{(4+5sinθ)/(5+4sinθ)}^2 + {3cosθ/(5+4sinθ)}^2 = 1,
これを使うと
(x+5/3)^2 + y^2 = (4/3)^2,
ただし x ≧ 5/3 - 3/5 = 16/15.
20/12/03 03:22:07.65 EylvoCB2.net
>>841
x = -3/(5+4sinθ),
y = 4(cosθ)/(5+4sinθ),
ところで
(4+5sinθ)^2 + (3cosθ)^2 = (5+4sinθ)^2,
{(4+5sinθ)/(5+4sinθ)}^2 + {3cosθ/(5+4sinθ)}^2 = 1,
これを使うと
(x+5/3)^2 + y^2 = (4/3)^2,
ただし x ≧ 5/3 - 3/5 = 16/15.