20/06/24 21:21:24.00 NoItLLRp.net
>>601
・∫[0,q] dt √(1-t^2) = ( arcsin(q) + q√(1-q^2) )/2
・∫[0,1]dz z^{3/2}/√(1-z) = B(5/2,1/2) = Γ(5/2)Γ(1/2)/Γ(3) = 3π/8
・∫[0,1] z*arcsin(√z) = 1/2*arcsin(1) - 1/4*∫[0,1]dz z^{3/2}/√(1-z) =
20/06/24 21:21:24.00 NoItLLRp.net
>>601
・∫[0,q] dt √(1-t^2) = ( arcsin(q) + q√(1-q^2) )/2
・∫[0,1]dz z^{3/2}/√(1-z) = B(5/2,1/2) = Γ(5/2)Γ(1/2)/Γ(3) = 3π/8
・∫[0,1] z*arcsin(√z) = 1/2*arcsin(1) - 1/4*∫[0,1]dz z^{3/2}/√(1-z) =