20/06/06 14:46:57.72 RyPojoqR.net
>>693
n/{2^(n+1)} = (n+1)/(2^n) - (n+2)/{2^(n+1)},
20/06/06 14:46:57.72 RyPojoqR.net
>>693
n/{2^(n+1)} = (n+1)/(2^n) - (n+2)/{2^(n+1)},
20/06/06 14:46:57.72 RyPojoqR.net
>>693
n/{2^(n+1)} = (n+1)/(2^n) - (n+2)/{2^(n+1)},