20/03/26 12:16:42 Toc1jVc8.net
>>658
訂正
√x=1+1/2(x?1)?1/8(x?1)^2+1/16(x?1)^3?5/128(x?1)^4+?
↓
√x=1+1/2(x-1)-1/8(x-1)^2+1/16(x-1)^3-5/128(x-1)^4+・・
まあ原文見てください（＾＾；
20/03/26 12:16:42 Toc1jVc8.net
>>658
訂正
√x=1+1/2(x?1)?1/8(x?1)^2+1/16(x?1)^3?5/128(x?1)^4+?
↓
√x=1+1/2(x-1)-1/8(x-1)^2+1/16(x-1)^3-5/128(x-1)^4+・・
まあ原文見てください（＾＾；