19/08/14 15:27:20.20 rg2Nhb+h.net
おサルさん、（>>692より）【必死のパッチ】やなｗｗ（＾＾；
>>775
”if i is chosen uniformly independently of that strategy”
のindex iについてｗｗ
これ下記の”Alexander Pruss Dec 19 '13 at 15:05 ”の抜粋なｗ
以下の応答を嫁めｗ（＾＾
要するに、力点は、But以下の文にあるってことと
前文の”if i is chosen uniformly independently of that strategy”の部分が未証明だってことよｗ
(参考)
URLﾘﾝｸ(mathoverflow.net)
Probabilities in a riddle involving axiom of choice Dec 9 '13
(抜粋)
sked Dec 9 '13 at 16:16 Denis
The Modification
I think it is ok, because the only probability measure we need is uniform probability on {0,1,…,N-1}, but other people argue it's not ok, because we would need to define a measure on sequences, and moreover axiom of choice messes everything up. a
answered Dec 11 '13 at 21:07
Alexander Pruss
Let's go back to the riddle. Suppose u￣ is chosen randomly. The most natural option is that it is a nontrivial i.i.d. sequence (uk), independent of the random index i which is uniformly distributed over [100]={0,...,99}.
In general, Mj will be nonmeasurable (one can prove this in at least some cases). We likewise have no reason to think that M is measurable. But without measurability, we can't make sense of talk of the probability that the guess will be correct.
Denis Dec 17 '13 at 15:21
Our choice of index i is made randomly, but for this we only need the uniform distribution on {0,…,n}. It is made independently of the opponent's choice.
つづき