19/05/17 07:44:47.35 8cC+5bmi.net
>>637
＜前振り＞
（>>465より）
URLﾘﾝｸ(mathoverflow.net)
Probabilities in a riddle involving axiom of choice edited Dec 9 '13 at 16:32 asked Dec 9 '13 at 16:16 Denis
(抜粋)
The Anwser:
If u^→ =(un)n∈N and v^→ =(vn)n∈N are sequences of real numbers,
we say that u^→ ～v^→ if there is M such that for all n>=M, un=vn.
Then ～ is an equivalence relation, and we can use the axiom of choice to choose one representant by equivalence class.
・・・
with 0<=i<=99
・・・
it will compute the index Mj from which the sequence matches the representant of its ?-class. He then takes M to be the maximum of the Mj+1
・・・
At most one mathematician will be wrong: the one who has the number i with Mi maximal.
（ここまでは、問いの説明部分）
(引用終り)
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