19/04/07 21:27:34.71 LqdgVJIS.net
1*2*3*√(1^2+1/2^2+1/3^2+2*(cos(y*log(1/2))/(2)+cos(y*log(1/3))/(3)+cos(y*log(2/3))/(2*3)))
y*log(1/2) mod 2π = y*log(1/3) mod 2π = y*log(2/3) mod 2π = π
y=-10.4361448987+2a*-10.4361448987=-6.58447432914+2b*-6.58447432914=-17.8407075424+2c*-17.8407075424
a,b,cが整数のときでもっとも３つの値が近しくなるときのyをもとめる
y≒69
1*2*3*√(1^2+1/2^2+1/3^2+2*(cos(69*log(1/3))/(3)+cos(69*log(1/2))/(2)+cos(69*log(2/3))/(6)))≒7