19/04/07 21:07:48.67 LqdgVJIS.net
2*3*5*√(1+cos(y*log(1/2))^2/2^2+cos(y*log(1/3))^2/3^2+cos(y*log(1/5))^2/5^2+
2*(1*cos(y*log(1/2))/2+cos(y*log(1/3))/3+cos(y*log(1/5))/5+cos(y*log(1/2))/2*(cos(y*log(1/3))/3+cos(y*log(1/5))/5)+cos(y*log(1/3))/3*cos(y*log(1/5))/5))
y*log(1/2) mod 2π = y*log(1/3) mod 2π = y*log(1/5) mod 2π = π
y=-10.4361448987+2a*-10.4361448987=-6.58447432914+2b*-6.58447432914=-4.49460296451+2c*-4.49460296451