19/04/28 03:34:45.61 8R5PQTIx.net
>>522
u=1-x、v=1-yとおいてu>vのとき
lim(p->∞)[(1-x)^p+(1-y)^p-(1-x)^p(1-y)^p]^1/p
=lim(p->∞)[u^p+v^p-(uv)^p]^1/p
=u lim(p->∞)[1+(v/u)^p-v^p]^1/p
=u 1^0 (∵x^y はx>0、y∈Rで連続)
=max{u,v}
=max{1-x,1-y}
v<uの時も同様。
u=vのとき
lim(p->∞)[(1-x)^p+(1-y)^p-(1-x)^p(1-y)^p]^1/p
=lim(p->∞)[u^p+v^p-(uv)^p]^1/p
=lim(p->∞)[2u^p-(uu)^p]^1/p
=u lim(p->∞)[2-u^p]^1/p
=u 2^0 (∵x^y はx>0、y∈Rで連続)
=max{u,v}
=max{1-x,1-y}