18/07/19 16:38:03.49 nPcIIs+O.net
>>857-861
実根(2つ)
z = (1±√5)/2 = φ，-1/φ
虚数根(12個?)
z = (1+√5)(-1±i√3)/4 = φω，φω~,
z = (1-√5)(-1±i√3)/4 = (-1/φ)ω，(-1/φ)ω~
z = -1±i√3 = 2ω，2ω~
z = -0.7660444431189780352 ± 0.6427876096865393263 ｉ
z = -0.1736481776669303489 ± 0.9848077530122080594 ｉ
z = 0.9396926207859083841 ± 0.34202014332566873304 ｉ
ただし
φ = (1+√5)/2 = 1.618034
ω = (-1+i√3)/2 = e^(ｉ(2π/3)),
ω~ = (-1-i√3)/2 = e^(-ｉ(2π/3)),