18/05/27 04:35:27.73 i5aSKt1a.net
>>483
S = 6xx - (3-√3)aa = 1
から
aa = (3+√3)(xx -1/6) … (1)
V(x) = x^3 -(1/3)a^3 … (2)
= x^3 - (1/3)(3+√3)^(3/2)･(xx -1/6)^(3/2),
V '(x) = 3xx - x(3+√3)^(3/2) x√(xx -1/6) = 0,
xで割って
3x = (3+√3)^(3/2) √(xx-1/6),
9xx = (3+√3)^3 (xx-1/6),
xx = (√3 +1)/15,
これを (1) に入れて
aa = (√3 -1)/10,
>>490 が出�