17/07/08 12:59:39.37 E7CWjLAg.net
>>54
補足
F(y) = F(-√2) + (√2 +y) {2 + (1 -(1/√2) +y)^2}
≧ F(-√2)
= 8 -5√2,
訂正
1 + sin(x)^5 + cos(x)^5
= (1/2) {1+sin(x)} {1+cos(x)} F(－sin(x)－cos(x))
= (1/4) (1+y)^2 F(-y),
≧ 0,
17/07/08 12:59:39.37 E7CWjLAg.net
>>54
補足
F(y) = F(-√2) + (√2 +y) {2 + (1 -(1/√2) +y)^2}
≧ F(-√2)
= 8 -5√2,
訂正
1 + sin(x)^5 + cos(x)^5
= (1/2) {1+sin(x)} {1+cos(x)} F(－sin(x)－cos(x))
= (1/4) (1+y)^2 F(-y),
≧ 0,