17/07/23 19:25:31.71 yTyAIG7a.net
>>184 >>201 >>214 を改造...
a+b+c = s、ab+bc+ca = t とおく。
{(a+c)s}^2 - 4(aa+ac+cc)t = (aa+ac+cc - t)^2 = δ
ss - 3t =｛(a-c)^2･t + δ}/(a+c)^2 ≧ t|(a-c)/(a+c)|^2,
17/07/23 19:25:31.71 yTyAIG7a.net
>>184 >>201 >>214 を改造...
a+b+c = s、ab+bc+ca = t とおく。
{(a+c)s}^2 - 4(aa+ac+cc)t = (aa+ac+cc - t)^2 = δ
ss - 3t =｛(a-c)^2･t + δ}/(a+c)^2 ≧ t|(a-c)/(a+c)|^2,