16/08/16 23:37:07.16 BueGbAd9.net
>>461
すみません。間違っていました。
A := x^3 - 2
B := x^2 + 2*x +2
C := x + 1
とおく。
A = (x - 2)*B + (2*x + 2) = (x - 2)*B + 2*C
B = (x + 1)*C + 1
1 = B - (x + 1)*C
2*C = A - (x - 2)*B
2 = 2*B - (x + 1)*2*C = 2*B - (x + 1)*{A - (x - 2)*B} = -(x + 1)*A + {2 + (x + 1)*(x - 2)}*B = -(x + 1)*A + (x^2 - x)*B
1 = (-1/2)*(x + 1)*A + (1/2)*x*(x - 1)*B