16/03/07 10:31:44.21 zWU1/WlS.net
>>859
p[n]=q[n-1]
q[n]=(2q[n-1]+r[n-1])/4 q[1]=1/4
r[n]=q[n-1]
q[n]=(2q[n-1]+q[n-2])/4
q[n]=√5/10*(((1+√5)/4)^n-((1-√5)/4)^n)
p[n]=((5-√5)((1+√5)/4)^n+(5+√5)((1-√5)/4)^n)/10
16/03/07 10:31:44.21 zWU1/WlS.net
>>859
p[n]=q[n-1]
q[n]=(2q[n-1]+r[n-1])/4 q[1]=1/4
r[n]=q[n-1]
q[n]=(2q[n-1]+q[n-2])/4
q[n]=√5/10*(((1+√5)/4)^n-((1-√5)/4)^n)
p[n]=((5-√5)((1+√5)/4)^n+(5+√5)((1-√5)/4)^n)/10