17/01/23 18:30:30.37 EqA4X0wX.net
>>437
(1) x≒0 で
φ(x)＝－x/(1-x)－(1/3)x^6－(4/3)x^7－(10/3)x^8－(20/3)x^9－(59/5)x^10－(99/5)x^11－(497/15)x^12－(284/5)x^13－(31454/315)x^14－…
(2)
φ (0)＝0,
φ '(0)＝-1,
φ "(0)＝-2,
φ^(3) (0)＝-6,
φ^(4) (0)＝-24,
φ^(5) (0)＝-120,
φ^(6) (0)＝-960,